Penjelasan dengan langkah-langkah:
6. ( x + 5 ) ( x - 1 )
7. ( 2x - 6 ) ( x + 2 )
8. a = 2. b = 5 c = 2
[tex]x1.2 = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac} }{2a} = \frac{ - 5 \frac{ + }{} \sqrt{ {5}^{2} - 4.2.2} }{2.2} = \frac{ - 5 \frac{ + }{} \sqrt{25 - 16} }{4} = \frac{ - 5 \frac{ + }{} \sqrt{9} }{4} = \frac{ - 5 \frac{ + }{} 3}{4} \\ x1 = \frac{ - 5 + 3}{4} = \frac{ - 2}{4} = - \frac{1}{2} \\ x2 = \frac{ - 5 - 3}{4} = \frac{ - 8}{4} = - 2[/tex]
9. a = 3 b= -3 c = -6
[tex]x1.2 = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac} }{2a} = \frac{ - ( - 3) \frac{ + }{} \sqrt{ {( - 3)}^{2} - 4.3.( - 6) } }{2.3} = \frac{3 \frac{ + }{} \sqrt{9 + 72} }{6} = \frac{3 \frac{ + }{} \sqrt{81} }{6} = \frac{3 \frac{ + }{} 9}{6} \\ x1 = \frac{3 + 9}{6} = \frac{12}{6} = 2 \\ x2 = \frac{3 - 9}{6} = \frac{ - 6}{6} = - 1[/tex]
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